Let's calculate the value of \( m \) given the expression:

\[
m = (8.74 \times 10^{13}) \times (9.109 \times 10^{-31}) \, \text{kg}
\]

We can break this down as:

\[
m = 8.74 \times 9.109 \times 10^{13 - 31} \, \text{kg}
\]

Now, let's compute the result.The value of \( m \) is approximately \( 7.96 \times 10^{-17} \, \text{kg} \).

Would you like more details or have any questions?

Here are some related questions:
1. How are scientific notation calculations handled in physics problems?
2. What is the significance of the \( 9.109 \times 10^{-31} \, \text{kg} \) constant?
3. How do exponents affect multiplication in scientific notation?
4. What are the typical applications of such small mass values?
5. How do we convert between different units of mass?

**Tip:** When multiplying numbers in scientific notation, always add the exponents for the powers of 10.

Explore the step-by-step calculation of mass using scientific notation: m = 8.74×10^13 × 9.109×10^-31 kg. Learn about scientific notation, multiplication of exponents, and physics constants in this detailed solution. Suitable for high school students, Grades 10-12.

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